Question

X(7x+2)-(x+1)² при x=

Answer 1

X(7x+2)-(x+1)²=7х²+2х-х²-2х-1=6х²-1=6(√12)²-1=72-1=71

Answer 2

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Решение:
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$x(7x + 2) - (x + 1)^{2} = 7 {x}^{2} + 2x - {x}^{2} - 2x - 1 = \\ = 6 {x}^{2} -1$
Если х = √12, то
$6 {x}^{2} - 1 = 6( \sqrt{12} {)}^{2} - 1 = \\ = 6 \times 12 -1 = 72 - 1 = 71$

Ответ: 71

Answer 3

To evaluate the expression X(7x+2)-(x+1)² at a specific value of x, we simply substitute the value of x into the expression wherever it appears.

Assuming that "X" is a constant or a variable separate from "x", we will assume it is meant to be "x" (lowercase), and substitute the value of x = ? into the expression:

x(7x+2)-(x+1)² at x=?

To evaluate this expression at x=?, we need to know the value of "?". Once we have that value, we can substitute it into the expression and simplify.