Question

Log 4 x + log 16 x + log 2 x = 7

Answer 1

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Answer 2

We can simplify the left-hand side of the equation using the properties of logarithms:

log 4 x + log 16 x + log 2 x = log (4 x * 16 x * 2 x) = log (128 x^3)

Now we have the equation:

log (128 x^3) = 7

We can rewrite this equation using the definition of logarithms:

10^7 = 128 x^3

Dividing both sides by 128, we get:

x^3 = 10^7 / 128 = 78125

Taking the cube root of both sides, we get:

x = (78125)^(1/3) ≈ 50.39

Therefore, the solution to the equation is x ≈ 50.39.