Question

(5-х)^2-(3х-2)*(2х+1)=х*(2-5х)

Answer 1

25-10х+ х²-6х²+4х-3х+2=2х -5х²
-11х=-27
х=2 5/27

Answer 2

Let's simplify and solve the given equation:

First, we can simplify the left side of the equation by expanding the square:

(5-x)^2 - (3x-2)*(2x+1) = (25 - 10x + x^2) - (6x^2 - x - 2) = x^2 - 16x + 23

Now, we can simplify the right side of the equation by multiplying out the terms:

x*(2 - 5x) = 2x - 5x^2

So the original equation becomes:

x^2 - 16x + 23 = 2x - 5x^2

Rearranging terms, we get:

6x^2 - 18x + 23 = 0

We can solve for x using the quadratic formula:

x = [18 ± sqrt(18^2 - 4(6)(23))] / (2*6) x = [18 ± sqrt(60)] / 12 x = (9 ± sqrt(15)) / 6

So the solutions to the equation are:

x = (9 + sqrt(15)) / 6 or x = (9 - sqrt(15)) / 6