Question

(2x+5)(x-6)+2 (3x+2)(3x-2)=5 (2x+1)+11 решите уравнение

Answer 1

X=64 и x=8
как-то так

Answer 2

Let's first simplify the left side of the equation using the distributive property:

(2x+5)(x-6) + 2(3x+2)(3x-2) = 5(2x+1) + 11

2x^2 - 7x - 60 + 18x^2 - 36 = 10x + 5 + 11

20x^2 - 10x - 86 = 0

Now we can solve for x using the quadratic formula:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

where a = 20, b = -10, and c = -86:

x = (-(-10) ± sqrt((-10)^2 - 4(20)(-86))) / 2(20)

x = (10 ± sqrt(100 + 6880)) / 40

x = (10 ± sqrt(6980)) / 40

x ≈ -0.724 or x ≈ 1.886

Therefore, the solutions to the equation are approximately x = -0.724 or x = 1.886.