Question

Y=x^3+1 y=0 x=-1 x=2 y=1-x^3 y=0 x=-2 x=1

Answer 1

0=-1+1 правильно

0=8+1 неправильно


0=1-(-8)=9 неправильно

0=1-(-1)=1+1=2 неправильно

Answer 2

To find the intersection points between the two equations, let's substitute the given values and solve for y:

For the equation y = x^3 + 1:

1. When x = -1: y = (-1)^3 + 1 = -1 + 1 = 0

2. When x = 2: y = (2)^3 + 1 = 8 + 1 = 9

Therefore, for y = x^3 + 1, we have the points (-1, 0) and (2, 9).

For the equation y = 1 - x^3:

1. When x = -2: y = 1 - (-2)^3 = 1 - (-8) = 1 + 8 = 9

2. When x = 1: y = 1 - (1)^3 = 1 - 1 = 0

Therefore, for y = 1 - x^3, we have the points (-2, 9) and (1, 0).

So the intersection points for the two equations are (-1, 0), (2, 9), (-2, 9), and (1, 0).