Question

8x(2x-5)-(4x-3)^2=14x+21

Answer 1

$8x(2x-5)-(4x-3)^2=14x+21\\16x^2-40x-(16x^2-24x+9)-14x-21=0\\16x^2-16x^2-40x+24x-14x-9-21=0\\-30x-30=0\\x=\frac{-30}{30}$

Ответ: -1.

Answer 2

Ответ: -1

Объяснение: раскрываем скобки и переносим все влево.

Answer 3

To solve the given equation, let's break it down step by step:

8x(2x - 5) - (4x - 3)^2 = 14x + 21

First, expand the squared term:

8x(2x - 5) - (16x^2 - 24x + 9) = 14x + 21

Next, distribute 8x to both terms inside the parentheses:

16x^2 - 40x - 16x^2 + 24x - 9 = 14x + 21

Combine like terms on the left side:

-16x + 24x - 40x = 14x + 21 + 9

-32x = 14x + 30

Now, isolate the variable terms on one side by adding 32x to both sides:

-32x + 32x = 14x + 30 + 32x

0 = 46x + 30

To isolate x, subtract 30 from both sides:

0 - 30 = 46x + 30 - 30

-30 = 46x

Finally, divide both sides by 46 to solve for x:

x = -30/46

Simplifying the fraction:

x = -15/23

Therefore, the solution to the given equation is x = -15/23.