Question

4^0.25log2(4) + 2log16(4)

Answer 1

Ответ: 3

Объяснение:

Упращение выражения через формулу

log a^y (a)= 1/y

Answer 2

To solve the expression 4^0.25log2(4) + 2log16(4), let's break it down step by step.

First, let's simplify the logarithms using the logarithmic properties:

log2(4) = log2(2^2) = 2log2(2) = 2(1) = 2

log16(4) = log16(2^2) = 2log16(2) = 2(log2(2^4))/log2(16) = 2(4)/4 = 2

Now, substitute the simplified logarithms back into the original expression:

4^0.25log2(4) + 2log16(4) = 4^0.25 * 2 + 2 * 2

Next, calculate the exponentiation and multiplication:

4^0.25 = √4 = 2

2 * 2 = 4

Finally, add the results together:

4^0.25log2(4) + 2log16(4) = 2 * 2 + 2 * 2 = 4 + 4 = 8

Therefore, the value of the expression 4^0.25log2(4) + 2log16(4) is 8.