Question

16а во второй степени - 40а + 25=

Answer 1

${16a}^{2} - 40a + 25 = {(4a - 5)}^{2}$

Answer 2

16а^2-40а+25 = (4а-5)^2.

Проверка:

(4а-5)^2 = 16а^2-2*4а*5+5^2 = 16а^2-40а+25.

Answer 3

To solve the equation, we need to simplify and then solve for the variable "a." Here's the step-by-step solution:

1. Start with the equation: 16a^2 - 40a + 25 = 0.

2. Try to factorize the equation. However, it seems difficult to factorize directly, so we'll use the quadratic formula.

The quadratic formula states that for an equation in the form ax^2 + bx + c = 0, the solutions for x are given by: x = (-b ± √(b^2 - 4ac)) / (2a)

In our equation, a = 16, b = -40, and c = 25. Substituting these values into the quadratic formula, we get:

a = 16, b = -40, c = 25

x = (-(-40) ± √((-40)^2 - 4 * 16 * 25)) / (2 * 16) x = (40 ± √(1600 - 1600)) / 32 x = (40 ± √0) / 32

Since the discriminant (b^2 - 4ac) is zero, there is only one solution.

3. Simplify the equation further:

x = (40 ± 0) / 32 x = 40 / 32 x = 5/4

Therefore, the solution to the equation 16a^2 - 40a + 25 = 0 is a = 5/4.