Answer 1

$2(x^2+5x+7)^2-(x^2+6+5x+1-1)=1; x^2+5x+7=a;\\2a^2-a+1-1=0; \\a(a-\frac{1}{2} )=0\\\left[\begin{array}{ccc}x^2+5x+7=0; D net+resheniiy\\x^2+5x+7=\frac{1}{2} \\\end{array}$

$> net+resheniiy$

Ответ: Решений нет.

Answer 2

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