Question

Найдите корень уравнения.

Answer 1

$\frac{3x+5}{5}- \frac{x+1}{3}=1 (*15) \\ 3(3x+5)-5(x+1)=15 \\ 9x+15-5x-5=15 \\ 4x=5 \\ x= \frac{5}{4}$

$\frac{5y-1}{15}- \frac{y}{5}= \frac{2y}{3} (*15) \\ 5y-1-3y=10y \\ 8y=-1 \\ y=- \frac{1}{8}$

$\frac{x+1}{9}- \frac{x-1}{6}= 2- \frac{x+3}{2}(*18) \\ 2(x+1)-3(x-1)=36-9(x+3) \\ 2x+2-3x+3=36-9x-27 \\ 8x=4 \\ x= \frac{1}{2}$

$\frac{12-x}{4}- \frac{2-x}{3}= \frac{x}{6} ( *12) \\ 3(12-x)-4(2-x)=2x \\ 36-3x-8+4x=2x \\ x=28$