Question

Катушка из медной проволоки имеет сопротивление R=10,8Ом. Масса медной проволоки равна m = 3,41 кг. Сколько витков провода N и какого диаметра d намотано на катушке?

Answer 1

Calculation of the Number of Turns and Diameter of the Wire on the Coil

To calculate the number of turns (N) and the diameter (d) of the wire wound on the coil, we need to use the given information about the resistance (R) and the mass of the copper wire (m).

The resistance of the copper wire is given as R = 10.8 Ω The mass of the copper wire is given as m = 3.41 kg.

To calculate the number of turns (N), we can use the formula:

N = (m / ρ) * (π * d^2 / 4)

where ρ is the resistivity of copper, which is approximately 1.7 x 10^-8 Ω·m.

To calculate the diameter (d) of the wire, we can rearrange the formula as follows:

d = sqrt((4 * N * ρ) / (π * m))

Let's calculate the values of N and d using the given information.

Substituting the values into the formulas:

N = (3.41 kg / (1.7 x 10^-8 Ω·m)) * (π * d^2 / 4)

d = sqrt((4 * N * (1.7 x 10^-8 Ω·m)) / (π * 3.41 kg))

Now, let's calculate the values.

Using the given values of R = 10.8 Ω and m = 3.41 kg, we can calculate N and d.

N = (3.41 kg / (1.7 x 10^-8 Ω·m)) * (π * d^2 / 4)

d = sqrt((4 * N * (1.7 x 10^-8 Ω·m)) / (π * 3.41 kg))

Please note that the specific values for N and d cannot be determined without additional information.