Question

Пассажирский поезд при торможении движется с ускорением 0.3 м/с2 и останавливается через 1 мин после начала торможения.Найти начальную скорость.

Answer 1

Problem Analysis

We are given that a passenger train decelerates with an acceleration of 0.3 m/s^2 and comes to a stop after 1 minute of braking. We need to find the initial velocity of the train.

Solution

To solve this problem, we can use the following kinematic equation:

v = u + at

Where: - v is the final velocity (which is 0 m/s since the train comes to a stop) - u is the initial velocity (which we need to find) - a is the acceleration (-0.3 m/s^2, negative because it is deceleration) - t is the time taken for braking (1 minute = 60 seconds)

Substituting the given values into the equation, we have:

0 = u + (-0.3) * 60

Simplifying the equation, we get:

0 = u - 18

Rearranging the equation to solve for u, we have:

u = 18 m/s

Therefore, the initial velocity of the passenger train is 18 m/s.

Conclusion

The initial velocity of the passenger train is 18 m/s.