Question

два резистора имеют сопротивление по одному то 1 ом,какова будет мощность тока если подключить к источнику постояного напрежения 1вольт 2резистора последователь ?2резистора поралельны (условия и решение помогите пажалуйста )?))

Answer 1

Calculation of Current and Power in Series Connection of Resistors

To calculate the current and power in a series connection of resistors, we need to use Ohm's Law and the power formula.

In a series connection, the total resistance is the sum of the individual resistances. So, for two resistors connected in series with resistances of 1 ohm each, the total resistance would be 1 + 1 = 2 ohms.

Calculation of Current

Using Ohm's Law, we can calculate the current flowing through the resistors. Ohm's Law states that the current (I) flowing through a resistor is equal to the voltage (V) across the resistor divided by the resistance (R) of the resistor.

In this case, the voltage across the resistors is 1 volt and the total resistance is 2 ohms. Therefore, the current flowing through the resistors can be calculated as follows:

I = V / R

I = 1 V / 2 Ω

I = 0.5 Amperes

So, the current flowing through the resistors when they are connected in series is 0.5 Amperes.

Calculation of Power

To calculate the power dissipated by each resistor, we can use the power formula. The power (P) dissipated by a resistor is equal to the current (I) flowing through the resistor squared, multiplied by the resistance (R) of the resistor.

For each resistor in the series connection, the current flowing through them is 0.5 Amperes and the resistance is 1 ohm. Therefore, the power dissipated by each resistor can be calculated as follows:

P = I^2 * R

P = (0.5 A)^2 * 1 Ω

P = 0.25 Watts

So, each resistor in the series connection will dissipate 0.25 Watts of power.

Calculation of Current and Power in Parallel Connection of Resistors

To calculate the current and power in a parallel connection of resistors, we need to use the formulas for total resistance, total current, and individual power.

In a parallel connection, the total resistance (R_total) is given by the reciprocal of the sum of the reciprocals of the individual resistances. So, for two resistors connected in parallel with resistances of 1 ohm each, the total resistance would be:

1/R_total = 1/R1 + 1/R2

1/R_total = 1/1 + 1/1

1/R_total = 2/1

R_total = 1/2 ohms

Calculation of Total Current

Using Ohm's Law, we can calculate the total current flowing through the parallel resistors. Ohm's Law states that the current (I_total) flowing through a resistor is equal to the voltage (V) across the resistor divided by the resistance (R) of the resistor.

In this case, the voltage across the resistors is 1 volt and the total resistance is 1/2 ohms. Therefore, the total current flowing through the resistors can be calculated as follows:

I_total = V / R_total

I_total = 1 V / (1/2) Ω

I_total = 2 Amperes

So, the total current flowing through the resistors when they are connected in parallel is 2 Amperes.

Calculation of Individual Power

To calculate the power dissipated by each resistor in a parallel connection, we can use the power formula. The power (P) dissipated by a resistor is equal to the current (I) flowing through the resistor squared, multiplied by the resistance (R) of the resistor.

For each resistor in the parallel connection, the current flowing through them is 2 Amperes and the resistance is 1 ohm. Therefore, the power dissipated by each resistor can be calculated as follows:

P = I^2 * R

P = (2 A)^2 * 1 Ω

P = 4 Watts

So, each resistor in the parallel connection will dissipate 4 Watts of power.

I hope this helps! Let me know if you have any further questions.