Question

Мяч брошен горизонтально из окна со скоростью v0=10м/с .на каком расстоянии упадёт мяч если окно находится на высоте 45 м?

Answer 1

Problem Analysis

We are given that a ball is thrown horizontally out of a window with an initial velocity of v0 = 10 m/s. We need to find the distance at which the ball will fall if the window is located at a height of 45 m.

Solution

To solve this problem, we can use the equations of motion for projectile motion. Since the ball is thrown horizontally, the initial vertical velocity is zero. The only force acting on the ball is gravity, which causes it to accelerate downward.

We can use the following equations of motion for projectile motion:

1. Vertical displacement (h): h = (1/2) * g * t^2, where g is the acceleration due to gravity (approximately 9.8 m/s^2) and t is the time of flight. 2. Time of flight (t): t = sqrt(2h / g) 3. Horizontal displacement (d): d = v0 * t, where v0 is the initial horizontal velocity.

Let's calculate the time of flight and the horizontal displacement of the ball.

Calculation

Given: - Initial vertical velocity (v0) = 10 m/s - Height of the window (h) = 45 m - Acceleration due to gravity (g) = 9.8 m/s^2

Using the equation for time of flight (t): t = sqrt(2h / g) = sqrt(2 * 45 / 9.8) = sqrt(90 / 9.8) = sqrt(9.18) ≈ 3.03 s.

Using the equation for horizontal displacement (d): d = v0 * t = 10 * 3.03 ≈ 30.3 m.

Answer

The ball will fall at a distance of approximately 30.3 meters from the window.

Please note that the calculations assume ideal conditions and neglect air resistance.