Question

Найти жесткость пружиниы, растянувщейся на 5 см под действием силы 4Н

Answer 1

Calculation of Spring Stiffness

To find the stiffness of a spring, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position. Mathematically, this can be expressed as:

F = k * x

Where: - F is the force applied to the spring (in Newtons) - k is the spring constant or stiffness (in Newtons per meter) - x is the displacement of the spring from its equilibrium position (in meters)

In this case, we are given that the spring is stretched by 5 cm (or 0.05 meters) under the action of a force of 4 Newtons. We can use this information to calculate the stiffness of the spring.

F = k * x 4 N = k * 0.05 m

To find the value of k, we can rearrange the equation:

k = F / x k = 4 N / 0.05 m

Calculating the value of k:

k = 80 N/m

Therefore, the stiffness of the spring is 80 Newtons per meter.