Question

Помогите, срочно. Запишіть рівняння гармонічних коливань сили струму в електричній лампі розжарювання, якщо амплітуда коливань сили струму 0,5А, а період коливань 0,02с. У момент початку спостереження сила струму в лампі максимальна.

Answer 1

I can help you with your question.

The equation of harmonic oscillations of current in an electric incandescent lamp is given by:

$$I(t) = I_0 \cos(\omega t + \varphi)$$

where $I(t)$ is the current at time $t$, $I_0$ is the amplitude of the current, $\omega$ is the angular frequency, and $\varphi$ is the initial phase.

To find the values of these parameters, we can use the given information:

- The amplitude of the current is 0.5 A, so $I_0 = 0.5$ A. - The period of the oscillations is 0.02 s, so the angular frequency is $\omega = \frac{2\pi}{T} = \frac{2\pi}{0.02} = 100\pi$ rad/s. - The initial phase is the angle that the current has at the beginning of the observation. Since the current is maximum at that moment, the cosine function is equal to 1, so $\varphi = 0$.

Therefore, the equation of the harmonic oscillations of current in the electric incandescent lamp is:

$$I(t) = 0.5 \cos(100\pi t)$$

I hope this helps. If you need more information, you can check the web search results that I found for you . Have a nice day!