Question

Льдина плавает в море, причем ее надводная часть имеет объем 150 см3. Определите объем всей льдины.

Answer 1

The question is about the volume of an iceberg that floats in the sea, with its above-water part having a volume of 150 cm3. To answer this question, we need to use the principle of buoyancy, which states that the weight of the displaced fluid is equal to the weight of the floating object. In other words, the volume of the submerged part of the iceberg is proportional to the density of the sea water, and the volume of the above-water part is proportional to the density of the ice.

The density of sea water is about 1025 kg/m3, and the density of ice is about 917 kg/m3. Therefore, the ratio of the submerged volume to the above-water volume is 1025/917, or about 1.12. This means that for every 1 cm3 of ice above the water, there are 1.12 cm3 of ice below the water. So, to find the total volume of the iceberg, we need to multiply the above-water volume by 1 + 1.12, or 2.12.

The above-water volume is given as 150 cm3, so the total volume is 150 x 2.12, or 318 cm3. This is the answer. The iceberg has a volume of 318 cm3, of which 150 cm3 is above the water and 168 cm3 is below the water.