Question

Мяч бросают вертикально вверх со скоростью 19 м/с считая сопротивление воздуха равным нулю определи через какое время после броска мяч окажется в наивысшей точке траектории движения ( при расчётах прими g=10 м/c квадратных )

Answer 1

Ответ:

t=1,9c

Объяснение:

Когда мяч окажется  в наивысшей точке траектории движения, его скорость будет равна 0. V=V₀-g*t, 0=19-10t, t=1,9c

Answer 2

Calculation of Time to Reach the Highest Point of Trajectory

To determine the time it takes for the ball to reach the highest point of its trajectory, we can use the kinematic equation for vertical motion:

y = y0 + v0y * t - (1/2) * g * t^2

Where: - y is the vertical position of the ball at time t - y0 is the initial vertical position of the ball (which is 0 in this case, as we are measuring from the ground) - v0y is the initial vertical velocity of the ball (which is 19 m/s upwards in this case) - g is the acceleration due to gravity (which is 10 m/s^2 downwards)

At the highest point of the trajectory, the vertical velocity of the ball will be 0. Therefore, we can set v0y to 0 and solve for t:

0 = v0y - g * t

Simplifying the equation, we get:

t = v0y / g

Substituting the given values, we have:

t = 19 m/s / 10 m/s^2

Calculating the result, we find:

t = 1.9 seconds

Therefore, after 1.9 seconds from the moment of the throw, the ball will reach the highest point of its trajectory.