Question

Велосипедист, двигаясь под уклон, прошел за 10 с50 м и развил скорость 10 м/с. С каким ускорениемДвигался велосипедист и какой была его скорость в на-чале уклона?​

Answer 1

Ответ:

Объяснение:

V=V₀+at=5м/с+0,2м/с²*10с=5м/с+2м/с=7м/с . Наверное так

Answer 2

Calculation of Acceleration and Initial Speed

To calculate the acceleration and initial speed of the cyclist, we can use the given information. The cyclist traveled a distance of 10 m in 50 seconds and reached a speed of 10 m/s.

The formula to calculate acceleration is:

Acceleration (a) = Change in velocity (Δv) / Time taken (Δt)

Since the cyclist started from rest, the initial velocity (u) is 0 m/s. The final velocity (v) is given as 10 m/s. The time taken (Δt) is 50 seconds.

Using the formula, we can calculate the acceleration:

a = (v - u) / Δt

a = (10 m/s - 0 m/s) / 50 s

a = 0.2 m/s^2

Therefore, the acceleration of the cyclist is 0.2 m/s^2.

To calculate the initial speed of the cyclist at the beginning of the slope, we can use the formula:

Final velocity (v) = Initial velocity (u) + (Acceleration (a) * Time taken (Δt))

Rearranging the formula to solve for the initial velocity (u):

u = v - (a * Δt)

Substituting the given values:

u = 10 m/s - (0.2 m/s^2 * 50 s)

u = 10 m/s - 10 m/s

u = 0 m/s

Therefore, the initial speed of the cyclist at the beginning of the slope is 0 m/s.

Summary:

The cyclist had an acceleration of 0.2 m/s^2 while moving uphill and had an initial speed of 0 m/s at the beginning of the slope.