Question

чтобы нагреть 0.5 кг жидкости от 20 С до 80 С понадобится 63 кдж теплоты Найти по этим данным удельную теплоемкость жидкости о таблице оеделите какая жидкость Потерями тепла пренебречь, пожалуйста полное решение ! Спасибо зарание !)

Answer 1

Q=cm(T2-T1)
63000=0/5*60*c
63000=30*c
c=2100 
Если не изменяет память, это бензин

Answer 2

Calculation of Specific Heat Capacity

To find the specific heat capacity of the liquid, we can use the formula:

Q = mcΔT

Where: - Q is the amount of heat energy transferred - m is the mass of the liquid - c is the specific heat capacity of the liquid - ΔT is the change in temperature

In this case, we have: - Q = 63 kJ (as given) - m = 0.5 kg (as given) - ΔT = (80 - 20) °C = 60 °C

Substituting these values into the formula, we can solve for c:

63 kJ = 0.5 kg * c * 60 °C

Simplifying the equation:

c = (63 kJ) / (0.5 kg * 60 °C)

Now, let's calculate the specific heat capacity using the given values.

c = (63 kJ) / (0.5 kg * 60 °C) = 2.1 kJ/(kg·°C)

Therefore, the specific heat capacity of the liquid is 2.1 kJ/(kg·°C).

Determining the Liquid

To determine the specific liquid based on the given data, we need additional information. Unfortunately, the provided information does not include any specific details about the liquid. Without additional data, it is not possible to determine the exact liquid.

Please note that the specific heat capacity of a substance is unique to that substance. Different liquids have different specific heat capacities. To identify the liquid, we would need more information or additional data.

Assumptions

In this calculation, we have made the following assumptions: - The heat transfer is efficient, and there are no significant heat losses to the surroundings. - The specific heat capacity of the liquid remains constant over the given temperature range. - The specific heat capacity of the liquid is not affected by the heating process.

Please let me know if there is anything else I can help you with!