
В одинаковые кастрюли с равными массами и равной температурой воды погрузили свинцовый и оловянный
шары одинаковой массыии температуры . Температура воды в кастрюле с оловянным шаром повысилась болше чем в кастрюле со свинцовым шаром. Одинаковое ли количество теплоты передали шары воде и кастрюле?

Ответы на вопрос




The transfer of heat between the spheres and the water
When two spheres of equal mass and temperature are submerged in identical pots of water, the temperature of the water in the pot with the lead sphere increases more than the temperature of the water in the pot with the tin sphere. The question asks whether the same amount of heat is transferred from the spheres to the water and the pots.
The amount of heat transferred between an object and its surroundings can be calculated using the equation:
Q = mcΔT
Where: - Q is the heat transferred - m is the mass of the object - c is the specific heat capacity of the material - ΔT is the change in temperature
In this case, the spheres have the same mass and temperature, so the only difference is the material they are made of (lead and tin). To determine whether the same amount of heat is transferred, we need to compare the specific heat capacities of lead and tin.
According to the search results, the specific heat capacity of lead is approximately 0.13 J/g°C, while the specific heat capacity of tin is approximately 0.23 J/g°C [[1]] [[2]]. The specific heat capacity represents the amount of heat energy required to raise the temperature of a substance by 1 degree Celsius per gram.
Since the spheres have the same mass and temperature, the heat transferred from each sphere to the water and the pot can be calculated using the equation mentioned earlier. However, since the specific heat capacities of lead and tin are different, the amount of heat transferred will also be different.
Therefore, the conclusion is that the same amount of heat is not transferred from the spheres to the water and the pots. The lead sphere transfers less heat compared to the tin sphere due to the lower specific heat capacity of lead.
Please let me know if you found this information helpful or if you have any further questions!


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