Question

Во время перемещения по участку цепи заряда,равного 3 Кл,электрическое поле выполнило работу 0,12 кДж.Определите напряжение цепи.Очень нужно)​

Answer 1

Ответ:

U=40 B

Объяснение:

A=0,12 кДж=120 Дж

q=3 Кл

U=?

A=P*t=U*I*t=U*q ⇒ U=A/q=120/3=40 B

Answer 2

Calculation of Voltage in the Circuit

To determine the voltage in the circuit, we can use the formula for work done by an electric field:

Work done (W) = Voltage (V) × Charge (Q)

Given that the work done by the electric field is 0.12 kJ (kilojoules) and the charge in the circuit is 3 kC (kilocoulombs), we can substitute these values into the formula to find the voltage:

0.12 kJ = V × 3 kC

To solve for V, we need to convert the units to joules and coulombs:

0.12 kJ = 0.12 × 1000 J = 120 J

3 kC = 3 × 1000 C = 3000 C

Now we can substitute these values into the equation:

120 J = V × 3000 C

To solve for V, we divide both sides of the equation by 3000 C:

V = 120 J / 3000 C

Calculating this expression gives us the voltage in the circuit.