Question

Артиллерийский тягач массой 9 т тронулся с места с ускорением 0.6 м/с^2 Определите его силу тяги (Н) если коэффициент сопротивления движению равен 0,07.

Answer 1

F- сила тяги

F1 - сила трения

F-F1=ma - по второму закону Ньютона

F1= µm      µ-коэф сопротивления

Отсюда

F= m(µ+a)

F= 9000кг(0,07+0,6м/с^2)=6030Н

Ответ : 6030Н

Answer 2

Calculation of the Tractive Force of the Artillery Tractor

To determine the tractive force of the artillery tractor, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a). In this case, the mass of the tractor is given as 9 tons, which is equivalent to 9000 kg, and the acceleration is given as 0.6 m/s^2.

Using the formula F = m * a, we can calculate the tractive force:

F = 9000 kg * 0.6 m/s^2

F = 5400 N

Therefore, the tractive force of the artillery tractor is 5400 Newtons (N)