Question

r концам цепи , состоящей из последоваьелбно включённых термистора и резистора с сопротивлением 1 кОМ подано напряжение 20 В. При комнатной температуре сила тока была 5 МА . Когда термистор опустили в горячую воду, cила тока в цепи стала 10 мА . Во сколько раз изменилось в результате нагрева сопротивление термистора ?

Answer 1

Даже мне, это очевидно, хоть и понятия не имею имею что такое термистор, хотя кажется понял ведь это ОЧЕВИДНО

Answer 2

Calculation of Resistance Change in the Thermistor

To calculate the change in resistance of the thermistor, we can use the formula for Ohm's Law: V = I * R, where V is the voltage, I is the current, and R is the resistance.

Given: - Voltage (V) = 20 V - Current (I) at room temperature = 5 mA = 0.005 A - Current (I) after immersing the thermistor in hot water = 10 mA = 0.01 A - Resistance (R) of the resistor = 1 kΩ = 1000 Ω

Using Ohm's Law, we can calculate the resistance of the thermistor at room temperature and after immersion in hot water.

At room temperature: - Voltage (V) = 20 V - Current (I) = 0.005 A - Resistance (R) = V / I = 20 V / 0.005 A = 4000 Ω

After immersion in hot water: - Voltage (V) = 20 V - Current (I) = 0.01 A - Resistance (R) = V / I = 20 V / 0.01 A = 2000 Ω

The resistance of the thermistor has changed from 4000 Ω at room temperature to 2000 Ω after immersion in hot water.

Therefore, the resistance of the thermistor has decreased by a factor of 2 (2000 Ω / 4000 Ω) as a result of heating.