Question

Одноатомный газ в количестве 10 моль совершает работу 2 кДж к нему подводится 3кДж теплоты. как изменится температура газа?

Answer 1

Q=A+dU
dU=Q-A=3-2=1кДж
U=3/2*v*R*dT
dT=2000/3*8.31*10=8,022 К

Answer 2

Calculation of Change in Temperature

To calculate the change in temperature of the gas, we can use the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system.

The equation for the first law of thermodynamics is:

ΔU = Q - W

Where: - ΔU is the change in internal energy of the system - Q is the heat added to the system - W is the work done by the system

In this case, we are given that the gas performs work of 2 kJ and receives 3 kJ of heat. We can assume that the work done by the gas is positive, as it is performing work on its surroundings.

Substituting the given values into the equation, we have:

ΔU = 3 kJ - 2 kJ

Simplifying the equation, we find:

ΔU = 1 kJ

The change in internal energy of the gas is 1 kJ.

To calculate the change in temperature, we can use the equation:

ΔU = nCvΔT

Where: - n is the number of moles of the gas - Cv is the molar specific heat capacity at constant volume of the gas - ΔT is the change in temperature

We are given that the gas is a monoatomic gas, which means its molar specific heat capacity at constant volume (Cv) is 3/2R, where R is the gas constant.

Substituting the values into the equation, we have:

1 kJ = 10 mol * (3/2R) * ΔT

Simplifying the equation, we find:

ΔT = (1 kJ) / (10 mol * (3/2R))

Now, let's calculate the change in temperature using the given information.