Question

Определите мощность горелки, если лёд массой 400г, взятый при температуре 0(град.С), полностью расплавился через 8 минут. Теплоемкостью сосуда пренебречь, считать, что вся выделяемая теплота идёт на нагревание воды

Answer 1

Мощность
N=Q/t
Время
t=8×60=480с
Количество теплоты плавления льда
Qпл=λm
Qпл=3,3*10^5×0,4=1.32*10^5Дж
N=1,32*105/480=275Вт
Ответ 275 Вт

Answer 2

Calculation of the Power of the Burner

To determine the power of the burner, we can use the formula for heat transfer:

Q = m * c * ΔT

Where: - Q is the heat transferred - m is the mass of the ice - c is the specific heat capacity of water - ΔT is the change in temperature

In this case, the ice with a mass of 400g is completely melted, so the heat transferred is equal to the heat required to melt the ice. We can assume that the initial temperature of the ice is 0°C, and the final temperature is 0°C (since it has completely melted).

The specific heat capacity of water is approximately 4.18 J/g°C Therefore, we can calculate the heat transferred as follows:

Q = m * c * ΔT = 400g * 4.18 J/g°C * (0°C - 0°C) = 0 J

Since the heat transferred is 0 J, this means that no heat was required to melt the ice. Therefore, the power of the burner can be considered negligible or zero.

Please note that this calculation assumes that all the heat generated by the burner is used to melt the ice and that the heat capacity of the container is negligible.