Question

Автомобиль массой 1т движется по горизонтальной дороге с ускорением 0,5м,с^2 Определить развиваемую двигателем силу тяги, если коэффициент трения при движении автомобиля равен 0,1

Answer 1

По 2 закону Ньютона:

На ось Х:

Fтяги - Fтр = ma

Fтяги = ma + Fтр (1)

На ось Y:

N = mg

Fтр = мю*N = мю * mg

Fтяги = ma + мю * mg (из 1)

Fтяги = 11000 * 0,5 + 0,1 * 11000 * 10 = 5500 + 11000 = 16500 Н = 16,5 кН

Ответ: сила тяги равна 16,5 кН

Answer 2

Calculation of the Engine Thrust Force

To determine the thrust force developed by the engine, we need to consider the mass of the car, the acceleration, and the coefficient of friction.

Given: - Mass of the car = 1 ton = 1000 kg - Acceleration = 0.5 m/s^2 - Coefficient of friction = 0.1

The thrust force developed by the engine can be calculated using the equation:

Thrust force = Mass of the car * (Acceleration + Coefficient of friction * g)

where g is the acceleration due to gravity (approximately 9.8 m/s^2).

Substituting the given values into the equation:

Thrust force = 1000 kg * (0.5 m/s^2 + 0.1 * 9.8 m/s^2)

Calculating the thrust force:

Thrust force = 1000 kg * (0.5 m/s^2 + 0.1 * 9.8 m/s^2) = 1000 kg * (0.5 m/s^2 + 0.98 m/s^2) = 1000 kg * 1.48 m/s^2 = 1480 N

Therefore, the engine develops a thrust force of 1480 N.