Question

Тело массой m = 10 кг брошено вертикально вверх со скоростью 20 м/с. Найти потенциальную энергию тела в наивысшей точке подъема, если на преодоление сопротивления расходуется 10 % всей энергии.

Answer 1

Eп= 0,9*Eк= 0,9*10*20*20/2=1800 Дж

Answer 2

Calculation of Potential Energy at the Highest Point

To find the potential energy of the body at the highest point of its ascent, we need to consider the initial kinetic energy and the energy lost due to resistance.

Given: - Mass of the body, m = 10 kg - Initial velocity, v = 20 m/s - Energy lost due to resistance = 10% of the total energy

The potential energy of an object at a certain height is given by the formula:

Potential Energy = m * g * h

where: - m is the mass of the object - g is the acceleration due to gravity (approximately 9.8 m/s^2) - h is the height above the reference point

First, let's calculate the initial kinetic energy of the body:

Kinetic Energy = (1/2) * m * v^2 Substituting the given values: Kinetic Energy = (1/2) * 10 kg * (20 m/s)^2

Now, let's calculate the energy lost due to resistance:

Energy Lost = (10/100) * Kinetic Energy

Finally, the potential energy at the highest point can be calculated by subtracting the energy lost from the initial kinetic energy:

Potential Energy = Kinetic Energy - Energy Lost

Let's perform the calculations:

Kinetic Energy = (1/2) * 10 kg * (20 m/s)^2 = 2000 J

Energy Lost = (10/100) * 2000 J = 200 J

Potential Energy = 2000 J - 200 J = 1800 J

Therefore, the potential energy of the body at the highest point of its ascent is 1800 J.

Note: The calculations assume that there is no other external force acting on the body during its ascent.