Question

Тележка массой 30кг движется со скоростью 4 м/с к покоящейся тележке массой 10кг. Определить с какой скоростью стала двигаться тележка,если скорость первой стала 2 м/с?

Answer 1

M₁=30 кг               закон сохранения импульса:
v₁=4 м/с               m₁v₁+m₂v₂=m₁v₁¹+m₂v₂¹; 
v₂=0                     m₁v₁=m₁v₁¹+m₂v₂¹;
m₂=10 кг              m₁v₁-m₁v₁¹=m₂v₂¹ ⇒ v₂¹=(m₁v₁-m₁v₁¹)/m₂;
v₁¹=2 м/с              v₂¹=(30*4-30*2)10=(120-60)/10=60/10=6 м/с;
___________       Ответ: v₂¹=6 м.
v₂¹-?

Answer 2

Problem Analysis

We have a cart with a mass of 30 kg moving with a velocity of 4 m/s towards a stationary cart with a mass of 10 kg. We need to determine the velocity of the cart after its velocity is reduced to 2 m/s.

Solution

To solve this problem, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

The momentum of an object is given by the product of its mass and velocity. Mathematically, momentum (p) is defined as:

p = m * v

Where: - p is the momentum of the object, - m is the mass of the object, and - v is the velocity of the object.

Let's denote the mass of the first cart as m1, the velocity of the first cart before the collision as v1, the mass of the second cart as m2, and the velocity of the second cart after the collision as v2.

According to the conservation of momentum, we have:

m1 * v1 = (m1 + m2) * v2

We are given the values of m1 (30 kg), v1 (4 m/s), and m2 (10 kg). We need to solve for v2.

Substituting the given values into the equation, we have:

30 kg * 4 m/s = (30 kg + 10 kg) * v2

Simplifying the equation, we get:

120 kg * m/s = 40 kg * v2

Dividing both sides of the equation by 40 kg, we find:

v2 = (120 kg * m/s) / 40 kg

Simplifying further, we get:

v2 = 3 m/s

Therefore, the velocity of the cart after its velocity is reduced to 2 m/s is 3 m/s.

Answer

The velocity of the cart after its velocity is reduced to 2 m/s is 3 m/s.