Question

тело находится на наклонной плоскости с углом наклона 30 градусов,чему равно ускорение,с которым скользит тело?(g=10м/с в квадрате)Решите полностью ))

Answer 1

Ось у направляем по пути движения тела. уравнение:

mgsinA = ma ; делим на m ; gsinA=a ; a=10*1/2=5м/с^2

Answer 2

Problem Analysis

We are given that an object is on an inclined plane with an angle of inclination of 30 degrees. We need to find the acceleration with which the object slides down the plane. The acceleration due to gravity is given as 10 m/s^2.

Solution

To solve this problem, we can use the formula for the acceleration of an object on an inclined plane:

a = g * sin(θ)

where: - a is the acceleration of the object, - g is the acceleration due to gravity (10 m/s^2), - θ is the angle of inclination of the plane (30 degrees).

Substituting the given values into the formula, we can calculate the acceleration:

a = 10 * sin(30)

Let's calculate the value of a.

Calculation

Using the formula a = 10 * sin(30), we can calculate the value of a.

a = 10 * sin(30) = 10 * 0.5 = 5 m/s^2

Therefore, the acceleration with which the object slides down the inclined plane is 5 m/s^2.

Answer

The acceleration with which the object slides down the inclined plane is 5 m/s^2.