Question

прямолинейный проводник длиной 2 м находится в однородном магнитном поле сила тока в проводнике равна 0.4 А и на проводник со стороны поля действует сила,по модулю равная 0,4 Н найдите модуль и направление вектора индукции магнитного поля

Answer 1

F=BILsina
B=F/(ILsina)
F- ампера сила
L длина
I- сила тока

Answer 2

Calculation of the Magnetic Field Induction

To find the magnitude and direction of the magnetic field induction, we can use the formula:

F = BIL

Where: - F is the force acting on the conductor, - B is the magnetic field induction, - I is the current flowing through the conductor, and - L is the length of the conductor.

Given: - Length of the conductor (L) = 2 m - Current flowing through the conductor (I) = 0.4 A - Force acting on the conductor (F) = 0.4 N

We can rearrange the formula to solve for the magnetic field induction (B):

B = F / (I * L)

Substituting the given values:

B = 0.4 N / (0.4 A * 2 m)

Simplifying the equation:

B = 0.4 N / 0.8 A*m

B = 0.5 T

Therefore, the magnitude of the magnetic field induction is 0.5 Tesla.

Direction of the Magnetic Field Induction

To determine the direction of the magnetic field induction, we can use the right-hand rule. According to the right-hand rule, if we point the thumb of our right hand in the direction of the current flow (from positive to negative), the fingers will curl in the direction of the magnetic field lines.

In this case, since the force is acting on the conductor from the side of the magnetic field, we can conclude that the magnetic field lines are perpendicular to the plane of the paper, pointing into the paper.

Therefore, the direction of the magnetic field induction is into the paper.

Please note that the calculations and explanations provided above are based on the information given in the question and the formulas used in physics.