Question

Автомобиль двигался с начальной скоростью 10 м/с.Он начал разгонятся с ускооением 2 м/с в квадрате.Какой путь он проехал за 3 с. Помогите решать, пожалуйста

Answer 1

S=V0t+(at^2)/2=10×3+9=39метров

Answer 2

Problem Statement

You have an automobile that initially moves with a speed of 10 m/s. It starts accelerating with an acceleration of 2 m/s². You want to find out the distance it traveled in 3 seconds.

Solution

To find the distance traveled by the automobile, we can use the equation of motion:

Distance (s) = Initial velocity (u) * Time (t) + 0.5 * Acceleration (a) * Time (t)²

Given: - Initial velocity (u) = 10 m/s - Acceleration (a) = 2 m/s² - Time (t) = 3 s

Substituting these values into the equation, we can calculate the distance traveled:

Distance (s) = 10 m/s * 3 s + 0.5 * 2 m/s² * (3 s)²

Let's calculate the distance using this equation.

Distance (s) = 10 m/s * 3 s + 0.5 * 2 m/s² * (3 s)²

Distance (s) = 30 m + 0.5 * 2 m/s² * 9 s²

Distance (s) = 30 m + 1 m/s² * 9 s²

Distance (s) = 30 m + 9 m

Distance (s) = 39 m

Therefore, the automobile traveled a distance of 39 meters in 3 seconds.

Answer

The automobile traveled a distance of 39 meters in 3 seconds.