Question

Участок проводника длиной 10 см находится в магнитном поле индукцией 50 мТл. Сила тока, протекающего по проводнику, 10 А. Какую работу совершает сила Ампера при перемещении проводника на 8 см в направлении своего действия? Проводник расположен перпендикулярно линиям магнитной индукции.

Answer 1

Cила Ампера
$Fa=IBLsin \alpha$

$sin90=1$

работа силы Ампера

$A=Fa*d=IBLsin \alpha *d=10*50*10 ^{-3} *0.1*1*0.08=4*10 ^{-3}$

$A=4*10 ^{-3} Dj=4mDj$ Ответ

Answer 2

Calculation of Work Done by the Ampere Force

To calculate the work done by the Ampere force when moving a conductor in the direction of its action, we need to use the formula:

Work (W) = Force (F) × Distance (d) × cos(θ)

Where: - Force (F) is the product of the current (I) and the magnetic field strength (B). - Distance (d) is the displacement of the conductor. - θ is the angle between the direction of the force and the direction of displacement.

In this case, the conductor is perpendicular to the lines of magnetic induction, so the angle θ is 90 degrees, and cos(θ) = 0.

Given: - Length of the conductor (d): 10 cm = 0.1 m - Magnetic field induction (B): 50 mT = 0.05 T - Current (I): 10 A - Displacement (d): 8 cm = 0.08 m

Using the formula, we can calculate the work done:

W = F × d × cos(θ) = I × B × d × cos(θ) = 10 A × 0.05 T × 0.08 m × cos(90°) = 0 J

Therefore, the work done by the Ampere force when moving the conductor 8 cm in the direction of its action is 0 J.

Please note