Question

Самолёт взлетает со скоростью 216км.ч. С каким ускорением он должен двигаться по взлётной полосе длиной 1,2км?

Answer 1

а-?

S=1.2km=1200m

V=216km/h=60 м/c

Vo=0 м/c так как самолёт начинает движение из состояния покоя.

 

S=V2-Vo2/2a    a=V2-Vo2/2S= 3600/1200x2=1.5 м/c2

 

Answer 2

Calculation of Acceleration

To calculate the acceleration of the airplane during takeoff, we can use the formula:

Acceleration = Change in Velocity / Time

In this case, the change in velocity is the final velocity minus the initial velocity. The initial velocity is 0 km/h (since the airplane starts from rest), and the final velocity is 216 km/h. The time taken to cover the distance of the runway is not given, so we cannot calculate the exact acceleration.

However, we can calculate the time taken to cover the distance of the runway using the formula:

Time = Distance / Velocity

Given that the length of the runway is 1.2 km and the velocity is 216 km/h, we can calculate the time taken.

Let's calculate the time first:

Time = 1.2 km / 216 km/h

Converting the distance and velocity to the same unit (meters and meters per second) for consistency:

Time = (1.2 km * 1000) / (216 km/h * (1000/3600))

Simplifying the equation:

Time = (1.2 * 1000) / (216 * (1000/3600))

Time = (1.2 * 1000) / (216 * 0.2778)

Time = 1200 / 60

Time = 20 seconds

Now that we have the time, we can calculate the acceleration:

Acceleration = Change in Velocity / Time

Acceleration = (216 km/h - 0 km/h) / 20 seconds

Converting the velocity to meters per second:

Acceleration = (216 km/h * (1000/3600)) / 20 seconds

Simplifying the equation:

Acceleration = (216 * 0.2778) / 20

Acceleration = 5.5556 m/s²

Therefore, the airplane must accelerate at approximately 5.56 m/s² along the runway during takeoff.