Question

При сжатии газа его объем уменьшился с 8 л до 5л, а давление повысилось на 60кПа. Найдите первоначальное давление. Процесс изотермический.

Answer 1

Вот решение,удачи)))

Answer 2

Problem Analysis

We are given that the volume of a gas is compressed from 8 L to 5 L, and the process is isothermal. We need to find the initial pressure of the gas.

Solution

In an isothermal process, the temperature remains constant. According to Boyle's Law, for an isothermal process, the product of the initial volume and pressure is equal to the product of the final volume and pressure:

P1 * V1 = P2 * V2

Where: - P1 is the initial pressure - V1 is the initial volume - P2 is the final pressure - V2 is the final volume

We are given that: - V1 = 8 L - V2 = 5 L - P2 = P1 + 60 kPa (since the pressure increased by 60 kPa)

Substituting the given values into the equation, we can solve for P1:

P1 * 8 L = (P1 + 60 kPa) * 5 L

Simplifying the equation:

8P1 = 5P1 + 300 kPa

3P1 = 300 kPa

P1 = 100 kPa

Therefore, the initial pressure of the gas is 100 kPa.

Answer

The initial pressure of the gas is 100 kPa.