Question

первый автомобиль проехал расстояние между двумя поселками за 3 часа без остановок, двигаясь прямолинейно и равномерно, а второй автомобиль ехал по тому же пути и с той же скороостью, но в середине пути сделал остановку на 1 час. Во сколько средняя скорость второго автомобиля меньше, чем первого?

Answer 1

V2=3/4*V1 

Тоесть в 4/3 раза скорость первого была больше. 

Answer 2

Calculation of Average Speed

To calculate the average speed of the second car compared to the first car, we need to consider the total distance traveled and the total time taken by each car.

The first car traveled the distance between the two villages in 3 hours without any stops. We don't have the exact distance between the villages, but we can use this information to calculate the average speed of the first car.

The second car also traveled the same distance and at the same speed as the first car, but it made a 1-hour stop in the middle of the journey.

To find the average speed of the second car, we need to subtract the time spent on the stop from the total time taken by the second car and then calculate the average speed.

Let's assume the average speed of both cars is v and the distance between the villages is d.

The average speed of the first car can be calculated as:

Average Speed of First Car = Distance / Time = d / 3 The average speed of the second car can be calculated as:

Average Speed of Second Car = Distance / (Time - Stop Time) = d / (3 - 1) = d / 2

Therefore, the average speed of the second car is d / 2.

Now, we can conclude that the average speed of the second car is half the average speed of the first car.

The average speed of the second car is half the average speed of the first car.

Please note that we don't have the exact values for the distance between the villages or the speed of the cars, so we can only provide a general conclusion based on the given information.