Question

Найдите жесткость пружины, растянувшийся под действием силы 4 Н на 5см

Answer 1

5 см - 0.05 м
4 : 0.05 = 80 Н/м

Answer 2

Calculation of the Spring Constant

To find the spring constant (k) of a spring that has been stretched by a force of 4 N over a distance of 5 cm, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position.

Hooke's Law can be expressed as:

F = kx

Where: - F is the force applied to the spring (4 N in this case) - k is the spring constant (to be determined) - x is the displacement of the spring (5 cm or 0.05 m in this case)

To find the spring constant (k), we rearrange the equation as follows:

k = F / x

Substituting the given values:

k = 4 N / 0.05 m

Calculating the value:

k = 80 N/m.

Therefore, the spring constant of the spring is 80 N/m.

Please note that the calculation assumes that the spring obeys Hooke's Law and that the relationship between force and displacement is linear within the given range.

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