Question

Во сколько раз увеличится сила давления груза на пол лифта при его движении вверх с ускорением a=3м\с по сравнению с силой давления в неподвижном лифте? Ускорение свободного падения 10м\с

Answer 1

P1/P2=m*(g+a)/m*g=g+a/a=10+3/10=1,3
Ответ: увеличится в 1,3 раза.

Answer 2

Calculation of the Increased Pressure Force on the Elevator Floor

To calculate the increased pressure force on the elevator floor when it is moving upwards with an acceleration of a = 3 m/s^2, we need to consider the force of gravity and the additional force due to acceleration.

The force of gravity acting on the elevator floor is given by the formula F = mg, where m is the mass of the elevator and g is the acceleration due to gravity. In this case, the acceleration due to gravity is given as g = 10 m/s^2.

The additional force due to acceleration can be calculated using Newton's second law of motion, which states that F = ma, where F is the force, m is the mass, and a is the acceleration. In this case, the acceleration is a = 3 m/s^2.

To find the total force on the elevator floor, we need to add the force of gravity and the additional force due to acceleration. Therefore, the total force can be calculated as:

F_total = F_gravity + F_acceleration = mg + ma

Now, let's substitute the values into the equation:

F_total = m(g + a)

Since we are comparing the force of pressure on the elevator floor when it is moving upwards with the force of pressure when it is stationary, we can express the ratio of the two forces as:

Ratio = F_total (moving upwards) / F_total (stationary)

To find the ratio, we need to divide the total force when the elevator is moving upwards by the total force when it is stationary.

Let's calculate the ratio:

Ratio = (m(g + a)) / (mg)

Simplifying the equation:

Ratio = (g + a) / g

Now, let's substitute the given values:

Ratio = (10 m/s^2 + 3 m/s^2) / 10 m/s^2

Simplifying further:

Ratio = 13 / 10

Therefore, the force of pressure on the elevator floor will increase by a factor of 1.3 when it is moving upwards with an acceleration of 3 m/s^2 compared to when it is stationary.

Please note that the above calculation assumes that the mass of the elevator remains constant during the upward movement.