Question

Два сопротивления R1=50 Om и R2=100 Om соединены параллельно и подключены к источнику с Эдс 6 В. Внутреннее сопротивление источника - 5 Om. Найти силу тока в цепи.

Answer 1

1)
Находим общее сопротивление при параллельном соединении
R = R₁*R₂/(R₁+R₂) = 50*100 / (50+100) ≈ 33 Ом

2)
Находим силу тока в цепи:
I = ЭДС / (R+r) = 6 / (33+5) ≈ 0,16 А

Answer 2

Calculation of Current in the Circuit

To find the current in the circuit, we can use Ohm's Law and the concept of equivalent resistance for resistors connected in parallel.

The formula for calculating the equivalent resistance of two resistors connected in parallel is:

1/R_eq = 1/R1 + 1/R2

Given that R1 = 50 Ω and R2 = 100 Ω, we can substitute these values into the formula:

1/R_eq = 1/50 + 1/100

Simplifying the equation:

1/R_eq = 2/100 + 1/100

1/R_eq = 3/100

Taking the reciprocal of both sides:

R_eq = 100/3 Ω

Now, we can calculate the current in the circuit using Ohm's Law:

I = E / (R_eq + r)

Where: - I is the current in the circuit - E is the electromotive force (EMF) of the source (6 V) - R_eq is the equivalent resistance of the resistors connected in parallel (100/3 Ω) - r is the internal resistance of the source (5 Ω)

Substituting the given values into the formula:

I = 6 / (100/3 + 5)

Simplifying the equation:

I = 6 / (100/3 + 15/3)

I = 6 / (115/3)

To divide by a fraction, we can multiply by its reciprocal:

I = 6 * (3/115)

Simplifying the equation:

I ≈ 0.1565 A

Therefore, the current in the circuit is approximately 0.1565 A.