Question

Помогите пожалуйста. Автомобиль массой 13,6 т, трогаясь с места, первые 50 м проходит за 8 секунд. Какова сила тяги двигателя автомобиля, если коэффициент сопротивления движению составляет 0,1?

Answer 1

F=ma+Fтр по 2 закону 
F=m*2a+k*m*g а=s\t g=10
F=13,6*2*6,25+0,1*13600кг*10=170+13600=13700H

Answer 2

Calculation of Engine Thrust Force

To calculate the thrust force of the car's engine, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration (F = m * a). In this case, the force we are looking for is the thrust force, the mass is the mass of the car, and the acceleration is the acceleration of the car.

Given: - Mass of the car (m) = 13.6 tons = 13,600 kg - Distance traveled (d) = 50 m - Time taken (t) = 8 seconds - Coefficient of resistance (k) = 0.1

To find the acceleration (a), we can use the equation of motion: d = (1/2) * a * t^2. Rearranging the equation, we get: a = (2 * d) / t^2.

Substituting the given values, we have: a = (2 * 50) / (8^2) = 100 / 64 = 1.5625 m/s^2.

Now, we can calculate the thrust force (F) using the formula: F = m * a.

Substituting the values: F = 13,600 kg * 1.5625 m/s^2 = 21,250 N.

Therefore, the thrust force of the car's engine is 21,250 Newtons.

Note: The calculation assumes that the only force acting on the car is the force of engine thrust and neglects other forces such as friction, air resistance, and rolling resistance. Additionally, the given sources do not provide specific information about the car model or engine specifications, so the calculation is based on general principles of physics.