Question

Автомобиль с грузом массой 5 т проходит по выпуклому мосту со скоростью 21,6 км/ч. С какой силой он давит на середину моста, если радиус кривизны моста 50 м?

Answer 1

Дано
m=5т=5000кг
v=21,6км./ч=6м/с
R=50м
g=10
Найти: F
Решение
OY:ma=mg-N
N=mg-ma=m(g-a)
N=F
F=m(g-a)
$a= \frac{v^2}{R}= \frac{6^2}{50}= \frac{36}{50}=0,72$
F=5000(10-0,72)=5000*9,28=46400H=46,4*10³ KH

Answer 2

Calculation of the Force

To calculate the force with which the car presses on the middle of the bridge, we can use the centripetal force formula:

F = (m * v^2) / r

Where: - F is the force - m is the mass of the car with the load (5 tons or 5000 kg) - v is the velocity of the car (21.6 km/h or 6 m/s) - r is the radius of curvature of the bridge (50 m)

Substituting the given values into the formula, we can calculate the force:

F = (5000 kg * (6 m/s)^2) / 50 m

Calculating this expression gives us the force exerted by the car on the middle of the bridge.

Let's calculate it step by step:

1. Convert the velocity from km/h to m/s: - 21.6 km/h * (1000 m/1 km) * (1 h/3600 s) = 6 m/s

2. Substitute the values into the formula: - F = (5000 kg * (6 m/s)^2) / 50 m

3. Calculate the expression: - F = (5000 kg * 36 m^2/s^2) / 50 m

4. Simplify the expression: - F = 180000 kg·m/s^2 / 50 m

5. Calculate the result: - F = 3600 kg·m/s^2

Therefore, the car exerts a force of 3600 kg·m/s^2 on the middle of the bridge.