Question

Какую скорость приобретет трогающийся от остановки автобус за 3с, если ускорение его 1,8 м/c²

Answer 1

V=v0+at
v0=0
V=at
V=1,8×3=5,4м/с
Ответ 5,4м/с

Answer 2

Calculation of Speed

To calculate the speed acquired by a bus starting from rest in 3 seconds with an acceleration of 1.8 m/s², we can use the following formula:

Final speed (v) = Initial speed (u) + (Acceleration (a) * Time (t))

Given that the initial speed (u) is 0 m/s (since the bus starts from rest), the acceleration (a) is 1.8 m/s², and the time (t) is 3 seconds, we can substitute these values into the formula:

v = 0 + (1.8 * 3)

Simplifying the equation:

v = 0 + 5.4

Therefore, the final speed acquired by the bus after 3 seconds will be 5.4 m/s.