Question

Участок цепи состоит из 3 резисторов. R1 = 4 Ом, R2 = 8 Ом, R3 = 8 Ом. Второй и третий резисторы соединены параллельно, а первый последовательно с ними. Напряжение на первом резисторе 12 В. Определите силу тока в каждом резисторе и в участке цепи.

Answer 1

Если что там где написано сила тока ее надо найти я хотел написать гайти силу тока у каждого резистора и общую силу тока

Answer 2

Calculation of Current and Voltage in the Circuit

To determine the current and voltage in each resistor and the circuit segment, we can use Ohm's Law and the rules for series and parallel resistors.

Given information: - R1 = 4 Ω - R2 = 8 Ω - R3 = 8 Ω - Voltage across R1 = 12 V

Calculation of Current in R1

Since R1 is connected in series with R2 and R3, the current flowing through R1 is the same as the total current in the circuit.

Using Ohm's Law: V = I * R

Substituting the given values: 12 V = I * 4 Ω

Solving for I: I = 12 V / 4 Ω = 3 A

Therefore, the current flowing through R1 is 3 A.

Calculation of Current in R2 and R3

Since R2 and R3 are connected in parallel, they have the same voltage across them.

Using Ohm's Law: V = I * R

Substituting the given values: V = 12 V (voltage across R1)

For R2: 12 V = I2 * 8 Ω

Solving for I2: I2 = 12 V / 8 Ω = 1.5 A

For R3: 12 V = I3 * 8 Ω

Solving for I3: I3 = 12 V / 8 Ω = 1.5 A

Therefore, the current flowing through R2 and R3 is 1.5 A each.

Calculation of Voltage in the Circuit Segment

The voltage across R1 is equal to the voltage across the parallel combination of R2 and R3.

Therefore, the voltage across the circuit segment is 12 V.

To summarize: - Current in R1 = 3 A - Current in R2 = 1.5 A - Current in R3 = 1.5 A - Voltage in the circuit segment = 12 V

Please let me know if you need any further clarification or assistance!