Question

Поезд,двигаясь под уклон, прошёл за 10 с путь 160 м и развил скорость 17 м/с. Какой была скорость поезда в начале уклона?

Answer 1

Используем основное уравнение движения S=(Uo+U)*t/2=>Uot+Ut/2, отсюда Uo=2S-Ut/t=320-170/10=15 м/с.

Answer 2

Calculation of Train Speed on an Incline

To determine the initial speed of the train on the incline, we can use the equation of motion for uniformly accelerated motion. The equation is as follows:

v^2 = u^2 + 2as

Where: - v is the final velocity (17 m/s) - u is the initial velocity (unknown) - a is the acceleration (due to the incline) - s is the distance traveled (160 m)

We can rearrange the equation to solve for the initial velocity (u):

u^2 = v^2 - 2as

Substituting the given values:

u^2 = (17 m/s)^2 - 2 * a * 160 m

Now, we need to find the acceleration (a) caused by the incline. Unfortunately, the given information does not provide the necessary data to directly calculate the acceleration. Therefore, we cannot determine the exact initial speed of the train on the incline.

Please provide additional information if available, such as the angle of the incline or any other relevant data, so we can assist you further.