Question

смесь кислорода и азота общей массой m=320 г при температуре t=20, и давление p=3 мпа занимает сосуд вместимостью v= 40 л.определить количество вещества на ходящегося в сосуде

Answer 1

PV=m/M*R*T
m1-водород
m2-азот
m=m1+m2
m1=m-m2
PV=(m-m2)/M*R*T
m2=m-(PVM/RT)
Это масса азота. В М подставь молярную массу водорода.
Как посчитаешь m2, массу водорода нужно найти по m1=m-m2

Answer 2

Calculation of the Amount of Substance in the Vessel

To determine the amount of substance present in the vessel, we can use the ideal gas law equation:

PV = nRT

Where: - P is the pressure of the gas (in this case, 3 MPa) - V is the volume of the vessel (in this case, 40 L) - n is the amount of substance (what we want to find) - R is the ideal gas constant (8.314 J/(mol·K)) - T is the temperature of the gas (in this case, 20°C or 293.15 K)

Rearranging the equation to solve for n, we have:

n = PV / RT

Now we can substitute the given values into the equation and calculate the amount of substance.

Given: - P = 3 MPa = 3 * 10^6 Pa - V = 40 L = 40 * 10^-3 m^3 - T = 20°C = 293.15 K

Using the ideal gas constant R = 8.314 J/(mol·K), we can calculate the amount of substance:

n = (3 * 10^6 Pa) * (40 * 10^-3 m^3) / (8.314 J/(mol·K) * 293.15 K)

Calculating this expression gives us the amount of substance in moles.