Question

Тело брошено вертикально вверх со скоростью 50 м/с. На какую высоту оно поднимется? Помогите пожалуйста

Answer 1

Дано:

V=50 м/с

V0=0 м/с

Найти:S

Решение:

S=

V=V0-gt

g=-10 м/с^2

50=0+10t

t=5 c

S=0-(-10*25)

S= 125 м

 

V0-это начальная скорость

g-ускорение свободного падения

Answer 2

Calculation of the Maximum Height Reached by an Object Thrown Vertically Upwards

To calculate the maximum height reached by an object thrown vertically upwards, we can use the equation for the motion of an object under constant acceleration. In this case, the object is thrown vertically upwards, so the acceleration due to gravity acts in the opposite direction to the motion.

The equation we can use is:

v^2 = u^2 + 2as

Where: - v is the final velocity of the object (which is zero at the maximum height), - u is the initial velocity of the object (which is 50 m/s in this case), - a is the acceleration of the object (which is equal to the acceleration due to gravity, approximately -9.8 m/s^2), - s is the displacement of the object (which is the maximum height we want to find).

Rearranging the equation to solve for s, we have:

s = (v^2 - u^2) / (2a)

Substituting the given values into the equation, we can calculate the maximum height reached by the object.

Let's calculate it step by step:

1. Substitute the values into the equation: - v = 0 m/s (final velocity) - u = 50 m/s (initial velocity) - a = -9.8 m/s^2 (acceleration due to gravity)

2. Calculate the maximum height (s): - s = (0^2 - 50^2) / (2 * -9.8) - s = (-2500) / (-19.6) - s ≈ 127.55 meters

Therefore, the object will reach a maximum height of approximately 127.55 meters when thrown vertically upwards with an initial velocity of 50 m/s.

Please note that air resistance is not considered in this calculation, and the value of acceleration due to gravity used is an approximation.