Question

Два одинаковых металлических шара имеют заряды 2 мкКл и -5 мкКл. Шары привели в соприкосновение и раздвинули на прежнее расстояние. Сравнить силы взаимодействия шаров до и после соприкосновения

Answer 1

До: F1=k*q1*q2/R^2=k*2*10^-6*5*10^-6/R^2=k*10^-11/R^2
После: q1=q2=q=q1+q2/2=1,5*10^-6
F2=k*2,25*10^-12/R^2
F1/F2=4,4

Answer 2

1) найдем какой заряд будет на каждом шаре после соприкасновения, по закону сохранения заряда, т.к. шары одинаковые q1'=q2'=(q1+q2)/2=(2-5)*10^-6/2=-2*10^-6 Кл
2) сила взаимодействия до соприкасновения
F1=k*|q1|*|q2|/r^2
3) сила взаимодействия после соприкасновения F2=k*|q1'|*|q2'|/r^2
4) отношение сил до и после: F1/F2=|q1|*|q2|/|q1'|*|q2'|=2*5*10^-12/2*2*10^-12=10/4=2,5 раза.
Ответ: -2мкКл ; сила до соприкасновения в 2,5 раза больше чем после соприкасновения.

Answer 3

The question you asked is about the electric force between two identical metal spheres with different charges before and after they touch each other. I found a web page that has a detailed answer to this question. Here is a summary of the answer:

- Before they touch, the spheres have charges of 2 μC and -5 μC, respectively. The electric force between them is given by the formula F1 = k * |q1| * |q2| / r^2, where k is a constant, q1 and q2 are the charges, and r is the distance between them. - After they touch, the spheres share their charges equally, since they are made of metal. The charge on each sphere is given by q1' = q2' = (q1 + q2) / 2 = -1.5 μC. The electric force between them is given by the formula F2 = k * |q1'| * |q2'| / r^2, where q1' and q2' are the new charges. - To compare the forces before and after they touch, we can take the ratio F1 / F2 = |q1| * |q2| / |q1'| * |q2'| = 2 * 5 * 10^-12 / 1.5 * 1.5 * 10^-12 = 4.4. This means that the force before they touch is 4.4 times greater than the force after they touch.

I hope this helps you understand the problem. If you want to see the full answer, you can visit the web page I found.