Question

В точке А к рычагу приложена сила 4 Н. какую вертикальную силу надо приложить к рычагу в точке В чтобы он остался в равновесии? L1=2 L2=6 F1 = 4Н F2=?

Answer 1

Вот так скорее всего...

Answer 2

Problem Analysis

To solve this problem, we need to calculate the vertical force that needs to be applied at point B to keep the lever in equilibrium. The lever is acted upon by a force of 4N at point A and an unknown force at point B. The distances from the forces to the pivot point are given as L1=2 and L2=6, respectively.

Solution

To find the vertical force F2 required at point B to keep the lever in equilibrium, we can use the principle of moments. The principle of moments states that for an object in equilibrium, the sum of the clockwise moments about any point is equal to the sum of the anticlockwise moments about the same point.

Let's denote the clockwise moment as positive and the anticlockwise moment as negative.

The equation for the equilibrium of moments can be expressed as: F1 * L1 = F2 * L2 Where: - F1 = 4N (force at point A) - L1 = 2 (distance from force F1 to the pivot point) - L2 = 6 (distance from force F2 to the pivot point)

Solving for F2: F2 = (F1 * L1) / L2

Substitute the given values: F2 = (4 * 2) / 6 F2 = 8 / 6 F2 = 4/3 F2 = 1.33N

So, the vertical force F2 that needs to be applied at point B to keep the lever in equilibrium is 1.33N.

Conclusion

The vertical force required at point B to keep the lever in equilibrium is 1.33N.