Question

При протекании через раствор нитрата серебра электрического заряда 1 Кл на катоде выделилось 1,11 мг серебра.Сколько на катоде выделится серебра при прохождении через раствор 1500 Кл электрического заряда

Answer 1

M1=k*q1
m2=k*q2
m1/m2=q1/q2
m2=m1*q2/q1=1,11*1500/1=166,5 мг

Answer 2

Calculating the Amount of Silver Deposited

To calculate the amount of silver deposited at the cathode when 1500 C of electric charge passes through a silver nitrate solution, we can use the information provided in the question.

Given: - Electric charge passed through the solution: 1500 C - Amount of silver deposited when 1 C of electric charge passes through the solution: 1.11 mg

We can use the following formula to calculate the amount of silver deposited: Amount of silver deposited = (Electric charge passed) × (Amount of silver deposited per unit charge)

Substituting the given values: Amount of silver deposited = 1500 C × 1.11 mg/C

Calculation:

Amount of silver deposited = 1500 C × 1.11 mg/C = 1665 mg

Therefore, when 1500 C of electric charge passes through the silver nitrate solution, 1665 mg of silver will be deposited at the cathode.