Question

Какое количество теплоты необходимо сообщить воде массой 10 г ,взятой при температуры 0 градусов,для того,чтобы нагреть ее до температуры кипения и испарить

Answer 1

Q=m*(c*(T2-T1)+lambda) = 0,01*(4200*(100-0)+2260000) = 26800 Дж = 26,8 кДж

Answer 2

Calculating the Heat Required to Heat and Vaporize Water

To calculate the amount of heat required to heat water from 0 degrees Celsius to its boiling point and then vaporize it, we can use the specific heat capacity of water and the heat of vaporization.

Given: - Mass of water, m = 10 g - Initial temperature, t1 = 0°C - Final temperature (boiling point), t2 = 100°C

Calculating the Heat Required to Heat Water to Boiling Point

The formula to calculate the heat required to raise the temperature of a substance is: Q = c * m * Δt, where: - Q = heat energy - c = specific heat capacity - m = mass - Δt = change in temperature

From the search results, the specific heat capacity of water is c = 4200 J/(kg°C).

Using the given values: Q1 = c * m * (t2 - t1) Q1 = 4200 * 0.01 * (100 - 0) Q1 = 4200 * 0.01 * 100 Q1 = 4200 J

Calculating the Heat Required to Vaporize Water

The formula to calculate the heat required to vaporize a substance is: Q2 = L * m, where: - Q2 = heat energy - L = heat of vaporization - m = mass

From the search results, the heat of vaporization of water is L = 2.3 * 10^6 J/kg.

Using the given values: Q2 = L * m Q2 = 2.3 * 10^6 * 0.01 Q2 = 2.3 * 10^4 J

Total Heat Required

The total heat required is the sum of the heat required to heat the water to its boiling point and the heat required to vaporize it: Total Heat (Q) = Q1 + Q2 Total Heat (Q) = 4200 J + 2.3 * 10^4 J Total Heat (Q) = 24200 J

Therefore, the total amount of heat required to heat 10 grams of water from 0°C to its boiling point and then vaporize it is 24200 joules.